Gradient of a Moreau envelope 2026-10-06
For proper lower semicontinuous convex functions, the Moreau envelope has gradient . This follows by subgradient inversion under convex conjugacy and the quadratic conjugate. Firm nonexpansiveness of the proximal residual makes the gradient -Lipschitz continuous.
Past exam of the mathematics course of the University of Cambridge 2016 iii Paper 325 1 iii Solution Created 2026-10-03 Updated 2026-10-06
Use the conventionThis proximal map is also the resolvent of a monotone operator . A proper lower semicontinuous convex function has an affine minorant, so the quadratic term makes this minimization coercive and strongly convex. A unique minimizer exists for every . Its subgradient optimality condition isThe Moreau–Yosida regularisation is . The conjugate of an infimal convolution and the quadratic conjugate giveThe factor here is essential. Apply subgradient inversion under convex conjugacy, followed by the subdifferential sum rule with the everywhere differentiable quadratic:The last equivalence is precisely the unique proximal minimization condition. ThusThis proves both existence and uniqueness of the subgradient, rather than only identifying a possible element. The finite convex function is therefore differentiable, with , the gradient of a Moreau envelope.
For completeness, monotonicity of applied to the two proximal conditions givesHence is firmly nonexpansive. Expanding the same inequality shows that is firmly nonexpansive too. In particular, is -Lipschitz continuous. None of this requires a bounded effective domain; the result applies to the next example as well.
Past exam of the mathematics course of the University of Cambridge 2016 iii Paper 325 1 ii Solution Created 2026-10-03 Updated 2026-10-06
Write for the infimal convolution. It is proper by the permitted hypothesis. If and are finite, choose within of their respective infima. For , put and . Convexity of and givesLet . If either endpoint value is infinite, the desired inequality is automatic. Thus the infimal convolution is convex, without assuming the infimum is attained.
For its convex conjugate, replace a negative infimum by a supremum and then change variables :The two suprema separate because and are independent. Properness of and makes each supremum strictly greater than , so this separation remains valid when one or both are . Therefore . This is the conjugate of an infimal convolution. The bounded-domain assumption is unnecessary for these two calculations; the assumed properness and lower semicontinuity of will be used when applying subgradient inversion under convex conjugacy.
Past exam of the mathematics course of the University of Cambridge 2017 iii Paper 326 3 6 Solution 2026-10-06
By the definition of the subdifferential, meansRearrangement bounds by , and equality is attained at . Taking the supremum in the definition of the convex conjugate gives . Conversely this equality bounds every member of that supremum and rearranges to the subgradient inequality. ThereforeApply the same argument to and use the Fenchel-Moreau theorem . With the canonical Hilbert identification of the bidual, the equality is also equivalent to . This proves subgradient inversion under convex conjugacy:The conditions include finiteness at the points in question; expressions involving are not subgradients merely by formal subtraction.
Past exam of the mathematics course of the University of Cambridge 2017 iii Paper 326 3 7 Solution 2026-10-06
Let and . The proximal operator optimality condition gives . By subgradient inversion under convex conjugacy, . Since , this is exactly the optimality condition defining . Uniqueness of both Hilbert proximal minimizers proves Moreau decomposition:Both terms belong to the same Hilbert space after dual identification. No orthogonality of the two terms is asserted for a general convex ; that stronger property pertains to special indicator/cone cases.