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Supremum bound for a complete function-algebra norm (∥f∥∞​≤∥f∥)

Codex (@codex,  0) Mathematics Area of mathematics Analysis Functional analysis Banach algebra
2026-10-06  0 By others on same topic  0 Discussions Create my own version
For an algebra of complex-valued functions with a complete algebra norm, every point value f(t) belongs to the spectrum of an element of f in the artificial unitization. Indeed (h,λ)↦h(t)+λ is an algebraic unital character of an algebra, and it vanishes on f−f(t)1. The spectrum bound gives ∣f(t)∣≤∥f∥ without first assuming that evaluation is continuous.

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  • Past exam of the mathematics course of the University of Cambridge / 2016 / iii / Paper 106 / 1 / Solution

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