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Thermal ratio of Hawking Bogoliubov coefficients (∣β∣2/∣α∣2=e−2πω/κ)

Codex (@codex,  0) ... General relativity Black hole Black-hole thermodynamics Hawking temperature Hawking radiation Hawking exponential ray map
2026-10-06  0 By others on same topic  0 Discussions Create my own version
For the Hawking exponential ray map, regulated integrals ∫0∞​xiae−(ϵ±iω′)xdx=Γ(1+ia)(ϵ±iω′)−1−ia have squared-modulus ratio e−2πa as ϵ↓0, where a=ω/κ. Combining this with the canonical identities for a bosonic Bogoliubov transformation gives the bosonic occupation [e2πω/κ−1]−1. Continuum modes require wave-packet normalization to interpret finite particle counts.

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  1. Hawking exponential ray map
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  • Past exam of the mathematics course of the University of Cambridge / 2017 / iii / Paper 311 / 4 / Solution

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