Past exam of the chemistry B course of the University of Cambridge 2025 Paper 2 B7 b ii Solution 2026-10-20
For the same pair of atoms, the harmonic approximation gives , where is the bond force constant and the reduced mass. The large shifts mainly reflect changes in from CO pi backbonding; the complexes are not distinguished simply by their total number of valence electrons.
has stronger net backbonding than . Both are group-6 M(0), , 18-electron complexes. The more spatially extended tungsten orbitals provide effective overlap with CO , consistent with the lower stretching frequency. As a simple same-mode force-constant comparison, , about a 2.3% reduction.
has appreciable but less C–O weakening than those hexacarbonyls. Ni(0) is and the complex is also 18-electron. The more contracted, lower-energy late-3d occupied orbitals give less effective donation into CO than the group-6 carbonyls in this comparison. Trimethylphosphine donates electron density and increases backbonding relative to an otherwise comparable less-donating nickel complex; that effect does not force its frequency below chromium's. Comparing different metals requires both orbital energies and overlap.
has very weak backbonding and a frequency above free CO. Cu(I) is and 18-electron here, but positive charge lowers its occupied orbital energies and suppresses backdonation. Sigma donation and the cation's electrostatic polarization can strengthen the internal C–O bond. Consequently the usual free-CO reference, about , lies below this cation's band. A blue shift is compatible with carbon coordination; it does not imply absence of a metal–CO bond. Coupled normal modes and measurement conditions limit literal extraction of a local bond force constant from one band.
Trimethylphosphine 2026-10-20
Trimethylphosphine is , an electron-releasing phosphine ligand. Comparison of its carbonyl complexes with other phosphines helps separate steric and electronic trends.