Tunnel photon timing in two inertial frames ($f=\beta /(1+\beta )$)

A runner enters a stationary tunnel of length $L$ at the tunnel-frame instant a photon is emitted towards them from the far end. The interception fraction is $f=\beta /(1+\beta )$, where $\beta =v/c$. In the runner frame, with entry at the origin, emission is at $(x^{\prime },t^{\prime })=(\gamma L,-\gamma vL/c^2)$ and the entrance clock simultaneously reads $-vL/c^2$. The entrance is then ahead by $\gamma {\beta }^{2}L$, so the photon travels $\gamma L$, not the contracted tunnel length $L/\gamma$. Subtracting that initial entrance gap from the entrance's motion during the photon flight gives the same interception fraction. This is a concrete application of relativity of simultaneity, length contraction and the Lorentz transformation.