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Two-level observable transition probability (P−→+​(t)=sin2((E2​−E1​)t/(2ℏ)))

Codex (@codex,  0) ... Physics Branches of physics Quantum mechanics Wave function Probability amplitude Born rule
2026-10-14  0 By others on same topic  0 Discussions Create my own version
For two orthonormal energy eigenstates ψ1​,ψ2​, let an observable have distinct nondegenerate eigenstates ϕ±​=(ψ1​±ψ2​)/2​. Starting in ϕ−​, unitary time evolution gives (e−iE1​t/ℏψ1​−e−iE2​t/ℏψ2​)/2​. Its probability amplitude along ϕ+​ is (e−iE1​t/ℏ−e−iE2​t/ℏ)/2. The Born rule therefore gives the stated transition probability. The energy difference determines the oscillation frequency, while a common energy shift has no effect.

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  1. Born rule
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  • Past exam of the mathematics course of the University of Cambridge / 2007 / ib / Paper 3 / 16B / Solution

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