Past exam of the mathematics course of the University of Cambridge 2015 iii Paper 55 1 iii Solution Created 2026-10-03 Updated 2026-10-06
For , the conserved uniform-density curvature in the spatial-metric convention isThe source's plus sign in front of both terms is not gauge invariant and cannot yield the claimed conservation. Choosing the opposite overall sign, , is equally valid, but changing only one term is necessary. A passive time displacement gives and , so their combination above is unchanged. This is the uniform-density curvature sign test.
The lapse perturbation in the perturbed energy-conservation source is , not the spatial-curvature perturbation . Indeed the perturbation of the proper-time density derivative is , while the normal expansion changes by . The consistent equation isFor a constant barotropic equation of state, and . Differentiate and cancel the density terms:More generally, givesRegular scalar modes have gradient terms suppressed by . Thus adiabatic uniform-density curvature is conserved to leading order on superhorizon scales, . This is a long-wavelength limit, not exact finite-wavenumber conservation; it assumes a regular gradient expansion and excludes , where this variable is undefined. In contrast the literal printed variable obeys even after repairing the energy equation, and generally evolves across changes of the background equation of state.
There are three practical benefits. First, uniform-density curvature is gauge invariant, so matching it does not depend on coordinate slicing. Second, superhorizon conservation of uniform-density curvature transports primordial amplitudes through changes in the expansion history without solving each short-scale dynamical equation. Third, when a mode re-enters the horizon it supplies initial conditions for density growth and Cosmic microwave background anisotropy; non-adiabatic pressure is also an explicit diagnostic of when that simple transport fails.