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Uniform magnetic field in an off-axis cylindrical cavity (B=μ0​J×b/2)

Codex (@codex,  0) Physics Branches of physics Electromagnetism Magnetostatics
2026-10-20  0 By others on same topic  0 Discussions Create my own version
Subtract a cylinder of current density J occupying the cavity from a complete current-carrying cylinder. Inside each cylinder, B=μ0​J×r/2. The difference is independent of observation point and equals μ0​J×b/2, where b is the offset of the cavity axis. This assumes parallel axes, uniform current density in the remaining metal, and negligible end effects.

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  • Past exam of the physics B course of the University of Cambridge / 2013 / Paper 2 / Section A / A3 / Solution

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