Deligne-Lusztig induction 2026-10-14
For a rational maximal torus , choose a Borel subgroup containing it with unipotent radical . The alternating compactly supported étale cohomology of , in the appropriate -isotypic component, defines the virtual character of . It is independent of the chosen Borel. When the Borel subgroup is rational, this is ordinary induction from its rational points after inflation of a group representation from .
Deligne-Lusztig theory 2026-10-14
Deligne-Lusztig theory constructs virtual characters of finite groups of Lie type from compactly supported étale cohomology of varieties associated with Frobenius and flags. Rational maximal tori and their finite-group characters provide induction data, while the geometry explains character orthogonality and cuspidality.
Frobenius kernel theorem 2026-10-14
For a Frobenius complement , a class function with satisfies . For each nontrivial of degree , the virtual character has norm one and positive degree by Frobenius reciprocity. It is therefore irreducible, restricts to and is identically on the candidate kernel . The intersection of the kernels of these characters is exactly : outside , separation follows from the character of the regular representation of . This proves normality; and then give the semidirect product.
Past exam of the mathematics course of the University of Cambridge 2002 iii Paper 2 1 a Solution Created 2026-10-03 Updated 2026-10-14
Let denote the irreducible characters of finite-dimensional complex group representations of . A generalized character, or virtual character, is an integral linear combination of these irreducible characters. A class function is a function constant on conjugacy classes. For class functions use the character inner productA p-elementary group is a direct product of groups , where is a p-group and is a cyclic group of order coprime to . An elementary subgroup is a subgroup of this form for some prime . Either factor may be trivial. This notion is different from an elementary abelian group.
Brauer's characterization of characters says that a complex class function on is a generalized character exactly when its restriction to every elementary subgroup is a generalized character there. Equivalently,The character orthogonality relations make these inner products the coefficients of the restrictions in their irreducible bases. The theorem detects the integral character lattice. An ordinary character of a representation additionally requires every global irreducible coefficient to be nonnegative; integrality alone characterizes virtual characters, not necessarily actual representations.
Past exam of the mathematics course of the University of Cambridge 2008 iii Paper 6 5 Solution Created 2026-10-03 Updated 2026-10-14
Write , where and is the character of an irreducible representation. An irreducible representation is a cuspidal representation of a finite reductive group exactly when its Harish-Chandra restriction to every proper rational Levi subgroup of a rational parabolic subgroup is zero.
The needed identity is the Harish-Chandra restriction of a Deligne-Lusztig character. For a rational parabolic subgroup , the torus case of the induction-restriction formula givesHere . The geometric meaning of the indexing condition is that only a rational conjugate of the inducing maximal algebraic torus lying in the Levi can survive taking -invariants. This is the established torus case of Deligne-Lusztig induction, valid without a restriction on ; it is not an appeal to an unrestricted induction-restriction conjecture. See Dudas and Michel's lectures, Theorem 14.4.
Suppose first that is an elliptic maximal torus, meaning it lies in no proper rational parabolic subgroup. For any proper rational , the indexing set in the displayed sum is empty. Indeed with would imply , itself a proper rational parabolic subgroup. Hence , and multiplication by gives . This proves cuspidality.
Conversely suppose for a proper rational parabolic subgroup. There is a unique Levi subgroup of containing this particular maximal algebraic torus: relative to , it is generated by and those root subgroups for which both the root and its negative occur in . Call it . Uniqueness and , imply , so this is a proper rational Levi. Transitivity of Deligne-Lusztig induction through this rational parabolic saysSet , allowing it to be a virtual character. Adjunction of Harish-Chandra induction and Harish-Chandra restriction, extended linearly to virtual characters, givesThus this Harish-Chandra restriction cannot vanish, so is not cuspidal. No positivity or irreducibility of is needed, and the sign in causes no cancellation problem. We have provedThe term elliptic maximal torus is relative to the ambient group: split central factors are allowed. The actual condition is absence of a proper rational parabolic subgroup containing .
Past exam of the mathematics course of the University of Cambridge 2013 iii Paper 3 2 d Solution Created 2026-10-03 Updated 2026-10-07
Put , and let . Sharp two-transitivity gives and . A nonidentity element fixes at most one point. Counting the nonidentity elements in the stabilizer subgroups shows that there are fixed-point-free elements. Let be this set together with the identity. We first prove it is a normal subgroup, rather than presuming that fixed-point-free elements are closed under multiplication.
For , and directly. Otherwise use complex characters of a finite group. Let be the permutation character and , the character of the permutation representation with its constant line removed. For every nontrivial irreducible character of , form the virtual characterIts values are at the identity and at every fixed-point-free element. At an element with one fixed point, conjugate it to ; induction gives , because there is exactly one fixed coset.
The identity and the fixed-point-free elements together contribute to the inner product. The remaining elements are partitioned into the nonidentity parts of the stabilizer subgroups. Hence character orthogonality givesA virtual character of norm one is plus or minus an irreducible character: its coefficients in the irreducible-character basis are integers whose squares sum to one. Its positive degree selects the plus sign. Thus each is an actual irreducible character.
For a group representation, holds exactly on its kernel: make the representation unitary and compare the sum of its unit-modulus eigenvalues with its dimension. All of therefore lies in the intersection of the kernels of the . Conversely, a nonidentity element fixing a point gives in . Some nontrivial irreducible character of has , since otherwise the regular representation of would not vanish at . ConsequentlyThis proves normality and subgroup closure. It has order and no nonidentity element fixing a point, so it is a regular permutation subgroup.
Now acts transitively by conjugation on : identify an element of with its image of and use transitivity of on the remaining points. Thus all nonidentity elements of have the same order. Taking a suitable power of one element shows this common order is a prime . By Cauchy's theorem no other prime divides , so is a -group. Its nontrivial center is -invariant, so transitivity forces the center to be all of . Therefore is elementary abelian of order .
Since is prime to , is the unique Sylow -subgroup of . Uniqueness makes it characteristic under every group automorphism. We have provedThe character argument supplies the regular kernel of a finite sharply two-transitive group; the final Sylow argument establishes the stronger characteristic assertion.
Write the virtual character as with integer coefficients and irreducible characters . Character orthogonality gives . Norm one forces exactly one coefficient to be or , and positive degree selects the positive sign.
Two-row alternating character cancellation 2026-09-28
For even , the virtual charactervanishes on every permutation having an odd cycle. Under the Frobenius characteristic map, the Jacobi–Trudi identity identifies its characteristic with the degree- part of , which contains only products of even-indexed power sums.