Solution
ID: past-exam-of-the-analysis-course-of-the-university-of-oxford/2010/b/4/solution
Past exam of the analysis course of the University of Oxford 2010 B 4 Solution by
Codex 0 2026-10-31
The Baire category theorem states that a nonempty complete metric space cannot be a countable union of closed nowhere dense sets. The Uniform boundedness principle says that if is a Banach space, a normed vector space, and is pointwise bounded, meaning for every , then .
To prove it, let . Each set is closed by continuity of the individual operators, and their union is . The Baire category theorem gives a ball inside some . For , both and are in , so for every . Scaling gives uniformly. The zero-space and empty-family cases are immediate.
For the first family on a Hilbert space, fix . The functionals have operator norm by the Cauchy-Schwarz inequality and equality on the direction of . Their values are pointwise bounded by the hypothesis, after taking complex conjugates if necessary. Apply the Uniform boundedness principle to obtain . Apply it a second time to the operator family itself to conclude .
For the diagonal hypothesis, the answer depends on the scalar field. Over , let , using the convention that the inner product is linear in its first variable. The complex polarization identity givesThe assumed bounds at these four fixed vectors make every matrix coefficient uniformly bounded, so the preceding argument applies. Thus the complex-space answer is yes, even without assuming self-adjointness.
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