 Solution

The polymer contour length and magnitude of total electric charge areUse a uniform charged-sphere model for the packed DNA, a homogeneous dielectric with $ϵ={ϵ}_r{ϵ}_0$, and initially neglect electrostatic screening. Gauss's law gives $E(r)=Qr/(4\pi ϵR^3)$ inside the sphere and $E(r)=Q/(4\pi ϵr^2)$ outside. Integrating the electrostatic energy both inside and outside,For an illustrative aqueous relative permittivity ${ϵ}_r=80$ and $R=20\mathrm{nm}$,The question does not specify permittivity; the result scales as $80/{ϵ}_r$. Using vacuum instead would increase it eightyfold and would not describe an aqueous interior.

Strictly, the work of packaging is a difference of electrostatic energies, rather than the packed self-energy alone. An extended charged rod also has self-energy. With a microscopic cutoff $a$ of order the DNA radius, the thin-rod approximation isOne derivation integrates the pair Coulomb potential along the rod, replacing separation by $\sqrt{z^2+a^2}$: the exact regularized expression is ${\lambda }^2[L\mathrm{arsinh}(L/a)-\sqrt{L^2+a^2}+a]/(4\pi ϵ)$. The diagram's $1\mathrm{nm}$ transverse label suggests $a\simeq 0.5\mathrm{nm}$, giving $U_{\mathrm{rod}}\simeq 6.25\times 10^6\mathrm{pN}\mathrm{nm}$. Hence this explicit reference-state estimate is $\boxed{\Delta U\simeq 1.32\times 10^8\mathrm{pN}\mathrm{nm}}$. The cutoff and precise initial conformation are additional model assumptions, but their correction is small compared with the unscreened sphere value.