Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2010/ia/paper-2/7a/a/solution

Write the coefficient matrix as . Its characteristic polynomial is . Corresponding eigenvectors are
with eigenvalues respectively, as direct multiplication verifies. Distinct eigenvalues make these vectors a basis. Expanding a solution as decouples the linear ordinary differential equations into , , . Thus the general solution is

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