Solution
ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2013/iii/paper-69/5/solution
Past exam of the mathematics course of the University of Cambridge 2013 iii Paper 69 5 Solution by
Codex 0 Created 2026-10-03 Updated 2026-10-07
Use the well-mixed natural ventilation model for a distributed floor source. Let the building height be , its volume be , its temperature excess be , and the exterior mass density be . Let be the coefficient of thermal expansion, so reduced gravity is . Convert the total heat input to the temperature-volume flux , where is specific heat capacity. If the quoted heat flux is per floor area, first multiply it by that area.
For effective opening area for pressure-driven ventilation, define the equal-opening hydraulic coefficient such that the signed throughflow obeys , with the total driving pressure divided by mass density. In the effective-area convention of question 6, each opening has discharge , so . The usual physical-area orifice law instead gives ; that prefactor does not affect the stability conclusions.
Set and . Positive denotes entry at the floor and exit at the roof. hydrostatic pressure and wind combine to giveBecause the inflowing air is at exterior temperature in either direction, the heat budget isThe well-mixed ventilation temperature balance at steady state is thereforeAll roots must satisfy and their appropriate flow-direction inequality; squaring a pressure relation without imposing those conditions could add spurious branches.
The assisting case has a unique positive solution and it is stable. For opposing wind, define . There is always one solution with , a buoyancy-dominated upward flow. Below , the heat-removal curve is . It is zero at both endpoints, and its maximum occurs at :For there are two downward-flow roots as well as the upward-flow root. Equivalently, setting and , the equilibrium curve isFor linear stability analysis of the opposing-wind ventilation bistability, linearize the heat budget: the eigenvalue is . The cooler downward root has and , so it is stable. The warmer downward root has and , so it is unstable and separates the two basins. The upward root has and is stable. At the two downward roots merge at a saddle-node bifurcation; above that value only the upward equilibrium remains.
For ventilation switching under wind and heating changes, increasing wind pressure or decreasing heat input both reduce , so both can create the pair of wind-driven equilibria. They nevertheless have different physical and transient effects. On the hot upward branch, implicit differentiation of shows that increasing increases , while decreasing decreases . Both reduce the upward ventilation rate, but only a wind change shifts .
Under slow parameter variation, a state follows its current stable branch while that branch persists; the upward branch does not disappear when wind increases or heating decreases. A sufficiently large abrupt wind increase can raise beyond the current temperature and place that state below the new unstable threshold, causing flow reversal and cooling towards the wind-dominated equilibrium. A jump insufficient to cross its basin boundary returns to the upward equilibrium.
At fixed , reducing a still-positive heat input cannot force an initially upward-flow state through : at that boundary the temperature balance has . Thus heat reduction alone does not cause that reversal in this model. Conversely, decreasing wind or increasing heat from the stable downward branch eventually destroys it at the fold and forces a switch to the upward branch, giving history dependence. Wind strengthening and heat reduction have the same effect on the steady dimensionless control parameter, but not the same temperature change or switching dynamics. These stability statements use quasi-steady opening flow and a single well-mixed temperature; other stratification or airflow-inertia models require their own stability analysis.
New to topics? Read the docs here!