Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2015/iii/paper-7/4/solution

Identify with the Boolean hypercube , with coordinatewise multiplication and normalized Haar measure assigning mass to each point. Its Bernoulli function is a Rademacher random variable. The Walsh functions on a hypercube are the Walsh characters , indexed by all subsets , including . Independence of the sign coordinates gives . There are characters, equal to the dimension of , so they form an orthonormal basis.
Flipping coordinate negates exactly when . Thus the coordinate-flip generator on a hypercube satisfies
For , Parseval identity gives . Equivalently its Dirichlet form of a Markov chain is
where flips coordinate .
Set and . Since , its Walsh expansion contains only sets of even size. Every nonconstant such set has , giving the even-function spectral gap on a hypercube
At each the Hahn-Banach theorem supplies a real supporting linear functional of norm at most one with ; for a complex normed space use the real part of a complex norming functional. At take . Convexity of the norm gives . Since , sum these inequalities to get . Therefore . Combining the two bounds yields the sharp Rademacher second-moment inequality
No smoothness of the norm is required. The constant is sharp: two equal nonzero real coefficients give modulus or with equal probabilities. This is the second-versus-first moment case of the Kahane-Khintchine inequality for arbitrary normed vector spaces.
For the complex-circle assertion, write each independent Steinhaus random variable as , where is uniform on and all quadrant signs are independent. Conditional on the angles, is a Rademacher sum with complex coefficients and . Its conditional second moment is , independent of the angles. The preceding inequality gives its conditional first moment at least . Average over the angles and square to obtain the Steinhaus first-moment lower bound

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