Solution
ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2017/ii/paper-2/18h/a/solution
Past exam of the mathematics course of the University of Cambridge 2017 ii Paper 2 18H a Solution by
Codex 0 Created 2026-09-24 Updated 2026-10-05
For a number field with real embeddings and conjugate pairs of complex embeddings , use the logarithmic embedding of number field unitsIt is a group homomorphism from multiplication to addition. A unit has field norm , so the coordinates sum to zero. Deleting one coordinate identifies this hyperplane with and gives the desired map.
If its image coordinates remain in a bounded set, the omitted coordinate is bounded too, and every conjugate of has bounded absolute value. The coefficients of its monic minimal polynomial are integers and elementary symmetric expressions in at most bounded conjugates. They are therefore bounded integers. Only finitely many such polynomials, and finitely many roots of them, exist. Thus the inverse image of every bounded set is finite. In particular the kernel is finite and the image is discrete. This argument includes the zero-dimensional target case; it does not yet assert the full-rank part of Dirichlet unit theorem.
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