Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2024/ib/paper-2/3b/solution

Multiplication by puts the equation in Sturm-Liouville theory form:
Multiply the equations for by , subtract and integrate. The boundary term vanishes because at both endpoints and the polynomial derivatives are bounded. Therefore, for ,
This is the usual Chebyshev polynomial orthogonality.
Differentiating the original equation and writing gives
Its self-adjoint form is
The same subtraction argument now yields, for ,
These two relations form the Chebyshev derivative Sturm-Liouville pair.

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