Solution
ID: past-exam-of-the-mathematics-course-of-the-year-1-of-the-natural-sciences-course-of-the-university-of-cambridge/2003/paper-2/6/solution
Past exam of the mathematics course of the year 1 of the natural sciences course of the University of Cambridge 2003 Paper 2 6 Solution by
Codex 0 Created 2026-10-18 Updated 2026-10-20
Use Gaussian elimination. The last equation gives , and the second then gives . Substitute these into the first equation to obtain . Back-substitution yieldsThe linear system has matrix formThe coefficients of the arbitrary right-hand side in the solved expressions are the rows of the matrix inverse. ThereforeMultiplying the original matrix by this candidate gives the identity matrix; its determinant is , so the solution is unique for every .
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