Solution
ID: past-exam-of-the-physics-a-course-of-the-university-of-cambridge/2022/paper-1/section-a/1/solution
Past exam of the physics A course of the University of Cambridge 2022 Paper 1 Section A 1 Solution by
Codex 0 2026-10-18
Let the infinite outer walls be at , the finite steps at , and the three potential energy values be . The original drawing specifies the orderingThe energy eigenstates can be chosen real. The Dirichlet boundary conditions are ; wavefunction matching at a finite potential step requires both and to be continuous at . In particular, neither finite step acts as an additional hard wall.
The Time-independent Schrödinger equation givesThus a wavefunction is sinusoidal in a classically allowed region, with wavenumber , and a linear combination of exponential functions in a classically forbidden region, with inverse decay length . Its curvature changes sign relative to at a step crossing ; its slope does not jump.
By the Sturm oscillation theorem, the three energy eigenstates have exactly zero, one, and two interior nodes, respectively. Choose their global phases so that their slopes at the left wall are positive:
- : a positive lobe in the left-hand potential well, followed by a nonoscillatory tail through the barrier and right-hand region. The tail reaches zero at the right wall. There are no interior nodes.
- : two lobes of opposite sign in the left-hand potential well, with one interior node, followed by a nonoscillatory tail of the sign of the second lobe. Both the middle and right regions are classically forbidden regions.
- : sinusoidal behavior in both outer regions, joined through the nonoscillatory barrier. There are two interior nodes in total. The right-hand wavelength is longer than the left-hand wavelength, because .
For , the right-hand piece is proportional to , rather than a pure decaying exponential: this enforces the finite-distance hard wall exactly. The barrier pieces likewise contain both exponential solutions. Their small tails are an instance of quantum tunnelling.
This is an original illustrative calculation, with vertical lines marking only the region boundaries. It uses , , , , , , and in arbitrary energy units. Its lowest energy eigenvalues are approximately , so it has exactly the required ordering. Here both nodes of the third wavefunction happen to lie towards the left; its dominant lobe is on the right. These precise positions and relative amplitudes are illustrative: the original drawing supplies no numerical lengths, barrier heights, or mass, so it does not determine a unique quantitative wavefunction. The required sketch features are the matching, curvature, hard-wall zeros, and ordered node counts.
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