 Solution

For monovalent mobile ions, the linearized Debye–Hückel screening length isHere $n_i$ is a number density in ${\mathrm{m}}^{-3}$, not a molarity. Use the question's idealized neutral-water convention, $c_{+}=c_{-}=10^{-7}\mathrm{mol}{\mathrm{L}}^{-1}$, and $T=293.15\mathrm{K}$. Both ion species contribute:For added salt concentration $c_s$ in $\mathrm{mol}{\mathrm{L}}^{-1}$, the ionic strength in this model is $I=c_s+10^{-7}\mathrm{mol}{\mathrm{L}}^{-1}$. With the numerical molarity $I_M=I/(1\mathrm{mol}{\mathrm{L}}^{-1})$,The water contribution is negligible at that salt level. The factor $10^3$ converts molarity into $\mathrm{mol}{\mathrm{m}}^{-3}$; omitting it or counting only one ion species gives a wrong screening length. Exact water autoionization and activities vary with temperature, so the first estimate uses the simplified neutral $10^{-7}\mathrm{M}$ concentrations implied by the question. At the higher salt level, ion-size effects, nonideal activities and changes in permittivity limit the numerical accuracy of this continuum estimate.