Solution

ID: past-exam-of-the-theoretical-mechanics-course-of-the-university-of-oxford/2009/b/4/d/solution

Retain the rigid-wall cosine in and the lower-wall cosine in :
The wave equation gives . The upper-wall condition gives , hence
For nonzero real , eliminating gives with , .
On every interval , the left side decreases from positive infinity to zero, while the right side is finite and positive. Continuity gives at least one intersection per interval for each . The functions are analytic between their poles, so roots are isolated there; their union over countably many intervals is a countably infinite set. Reflection gives the redundant negative- solutions. For , the limiting formal root is the zero-frequency gauge mode, not one of these positive-frequency branches.
Figure 1.
Real vertical-mode intersections for three horizontal mode numbers
. Details.
The graph uses representative dimensionless values and ; the interval argument applies for all positive values. For fixed and fixed branch , take . The positive right side becomes large, forcing the intersection towards the tangent pole from the right:
More precisely, if , then . Therefore the requested real-branch frequencies satisfy
The limiting upper condition is effectively pressure release for these acoustic branches. No claim is made here about imaginary or other complex branches, which were excluded from the requested analysis.

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