Solution

ID: past-exam-of-the-year-1-of-the-computer-science-course-of-the-university-of-oxford/2022/digital-systems-linear-algebra-introduction-to-formal-proof-resit/5/d/solution

Let for a real eigenvalue and a nonzero real eigenvector . Part (b) gives and . The expression for in part (c) therefore gives
Consequently is a real eigenvalue of , with the same eigenvector . For a real matrix and real eigenvalue, a nonzero real vector can be chosen in the real kernel of ; no complex-vector assumption is needed.

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