Past exam of the mathematics course of the University of Cambridge 2019 ii Paper 2 12G i Created 2026-09-24 Updated 2026-10-03
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Past exam of the mathematics course of the University of Cambridge 2019 ii Paper 1 9B Solution Created 2026-09-24 Updated 2026-09-29
For an infinitesimal test mass on the surface of a homogeneous sphere, its Newtonian mechanical energy isThe spatially flat case corresponds to zero specific energy. Usingand dividing by givesSince is proportional to the scale factor , this is the Newtonian derivation of the flat Friedmann equation
Now take and . PutThe contracting branch of the Friedmann equation isIntegrating from givesThereforeon the contracting interval, reaching at .
Past exam of the mathematics course of the University of Cambridge 2019 ii Paper 1 8E b Created 2026-09-24 Updated 2026-09-24
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Past exam of the mathematics course of the University of Cambridge 2019 ii Paper 1 6C Solution Created 2026-09-24 Updated 2026-09-29
In this discrete age-structured population model, individuals of age present during the breeding season each produce newborns, so the number entering age zero isAn age- individual survives the following winter with probability and is then age in the next year, givingTogether with the initial age distribution, these equations determine every later cohort.
Substitute into the survival equation. Thenand iteration givesThe birth equation becomesA nonzero population mode therefore requires the Discrete Euler-Lotka equation
For nonnegative vital rates with at least one surviving reproductive age and enough decay to make the series finite, is continuous and strictly decreasing on , tends to infinity as , and tends to zero as . The intermediate value theorem gives one positive solution, and strict monotonicity makes it unique.
The value is the expected lifetime offspring count under these fixed rates. Since decreases, places the root at and the population grows geometrically; places it at and the population shrinks. Equality gives replacement, .
Past exam of the mathematics course of the University of Cambridge 2019 ii Paper 1 5J Solution Created 2026-09-24 Updated 2026-09-29
An exponential dispersion family has densities of the formwhere is the canonical parameter, is the dispersion parameter, and the support does not depend on . Its mean and variance are
For the given Gamma distribution, setThengivesThus the gamma laws form the Gamma exponential dispersion family.
Directly integrating, or using the cumulant-generating function of a gamma distribution,soDifferentiation at zero yields
Past exam of the mathematics course of the University of Cambridge 2019 ii Paper 1 4H c Created 2026-09-24 Updated 2026-09-24
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