Past exam of the mathematics course of the University of Cambridge 2023 ii Paper 3 10D a by
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Past exam of the mathematics course of the University of Cambridge 2023 ii Paper 2 9B Solution by
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The given formula is the integral of the Planck photon distribution. SetThenwhereEach photon of frequency has energy , so the energy density isThis is the temperature scaling of thermal photon number and energy densities.
After decoupling, cosmological redshift givesThe occupation number is conserved along the freely propagating photon trajectory. Its exponential argument at decoupling becomesThus the spectrum still has the Planck form ifFrequency and temperature redshift by the same factor, which is the redshift preservation of a thermal photon spectrum.
Past exam of the mathematics course of the University of Cambridge 2023 ii Paper 2 8D Solution by
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A fixed space frame is an inertial orthonormal frame whose axes remain fixed in space. A principal body frame is attached to the rigid body and aligned with the principal axes of its inertia tensor, so that the tensor is diagonal with entries .
If are the body axes and is the angular velocity, then the derivative of a body-fixed basis vector isIn the principal frame,For torque-free motion, the angular momentum has zero space derivative. ThereforeTaking body-frame components gives the Euler equations for a torque-free rigid body:
For an axisymmetric body, put and let be its symmetry axis. Decompose . ThenThus is a linear combination of and , proving that the angular momentum, angular velocity, and symmetry axis are always coplanar. This is the coplanarity in a torque-free axisymmetric rigid body.
Past exam of the mathematics course of the University of Cambridge 2023 ii Paper 2 7E Solution by
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For , absolute convergence permits separation into odd and even terms:Using the defining integral of the Gamma function and the substitution givesTermwise integration is justified by absolute convergence when , and the geometric sum isConsequently the Dirichlet eta function satisfies
Near zero the integrand is , while at infinity it decays exponentially. The integral therefore defines a holomorphic function for . Thusprovides the desired continuation wherever the displayed denominator is nonzero. At a nonreal zero of , use insteadwith an integer for which ; the bounded partial sums of give convergence for . This shows that those apparent singularities are removable and yields the Analytic continuation of the Riemann zeta function to the right half-plane.
Past exam of the mathematics course of the University of Cambridge 2023 ii Paper 2 6C b by
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Past exam of the mathematics course of the University of Cambridge 2023 ii Paper 2 6C a by
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Past exam of the mathematics course of the University of Cambridge 2023 ii Paper 2 5J Solution by
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The commands choose observations and predictors; generate a matrix of independent standard-normal values; generate independent binary random variables with success probability ; and report the observed number of successes, . The first
glm call then fits the Bernoulli logistic-regression modelThe prediction command returns the fitted response probabilities and sums them.The likelihood isAt the maximum-likelihood estimator, the intercept component of the score function isThereforeexactly, by the fitted-mean balance for logistic regression with an intercept.
The second fit uses probit regression,where is the standard normal distribution function. Its intercept score isa weighted residual equation. It does not imply , so exact equality is not expected. The output should nevertheless be close to : the data were generated with constant success probability independently of , so the fitted slopes should be small, the linear predictors should cluster near a common intercept, and the score weights should be nearly constant.
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Past exam of the mathematics course of the University of Cambridge 2023 ii Paper 2 41C d by
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Past exam of the mathematics course of the University of Cambridge 2023 ii Paper 2 39C c by
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