Past exam of the mathematics course of the University of Cambridge 2008 iii Paper 33 4 Solution Created 2026-10-03 Updated 2026-10-14
Use the primitive real-analytic Eisenstein series with exactly the normalization in the PDF. Its coset expression uses , so primitive bottom rows differing by sign represent the same coset. The factor in the primitive-pair sum accounts for this sign identification. Unlike the sum over all nonzero integer pairs, this Eisenstein series has no additional factor . Write for the Rankin–Selberg integral parameter and for the Dirichlet series parameter to keep their shift visible.
First establish an initial region where all rearrangements are absolute. The invariant norm of a modular form is bounded: it is -invariant, continuous on a truncated fundamental domain, and tends to zero at the cusp. Integrating one period of the Fourier series givesWith , this proves the Fourier coefficient bound for a cusp form , and similarly . Hence is initially absolutely convergent for .
For , the primitive real-analytic Eisenstein series is locally uniformly convergent and holomorphic in . On the standard fundamental domain it has at most polynomial growth in , locally uniformly in this half-plane. These are the analytic properties of the Eisenstein series needed here; they can also be checked directly from its defining sum. For example, for real and , majorize the primitive sum by the sum over all nonzero pairs and useThis bound follows by comparing a shifted one-dimensional sum with its integral and a largest summand. Summing over gives . For complex , , and the estimates are uniform on compact parameter sets. Since and decay exponentially on the cusp end, the integral is therefore holomorphic throughout by dominated integration.
The product is -invariant: the two modular factors cancel the transformation . With the hyperbolic area , Rankin–Selberg unfolding gives, initially for ,Absolute unfolding is justified by replacing by and using the same finite fundamental-domain integral with . The subsequent termwise integrations can be justified particularly economically by Cauchy-Schwarz inequality: on each horizontal line,The coefficient bounds make the right side as , and it decays exponentially as . Multiplication by is integrable at zero when . Thus the integral of the inner Fourier series may be evaluated first. Orthogonality of the exponentials givesThe Mellin transform of each exponential isIn the same initial region the sum of the absolute values of these integrals is finite by . Consequently the exact Rankin–Selberg integral identity isIn particular the two parameters are not equal: the Dirichlet series argument is shifted by .
The holomorphy of on now gives the required continuation:The right side agrees with the original Dirichlet series on and is holomorphic on the larger half-plane. No continuation of the Eisenstein series beyond is needed.
It is important to supply a further argument for absolute convergence: analytic continuation alone does not imply it. For real , both and are nonnegative, and their fundamental-domain integral is finite by the cusp estimates above. Tonelli theorem therefore unfolds even before knowing convergence of the Dirichlet series. On each fixed horizontal line, the Fourier series converges absolutely and uniformly, so integration in givesA second use of Tonelli theorem, now in , proves the positive unfolding of a cusp-form square:Since every real has with , we have absolute convergence of for . Absolute convergence for complex follows by taking its real part. In fact Cauchy-Schwarz inequality also gives absolute convergence of there from the two corresponding square sums.
Finally let and choose . The preceding square-coefficient bound and Cauchy-Schwarz inequality giveThis proves absolute convergence of cusp-form L-series from square coefficients, and henceEquivalently, the suggested elementary inequality works by choosing : after multiplication by its two bounds sum to a convergent and a convergent . The existence of this interval is precisely .