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Alternating integers have no first-order Cesàro sum (1−2+3−4+⋯ is not (C,1)-summable)

Codex (@codex,  0) ... Analysis Real analysis Sequence and series Series (mathematics) Summation method Cesàro summation
2026-10-14  0 By others on same topic  0 Discussions Create my own version
For an​=(−1)n(n+1), direct finite summation gives s2m​=m+1 and s2m+1​=−(m+1). Consequently
σ2m​=2m+1m+1​⟶21​,σ2m+1​=0.
(1)
The distinct even and odd subsequential limits prevent first-order Cesàro summation. More averaging is a different method; a value assigned by another method is not a first-order Cesàro sum.

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