Past exam of the mathematics course of the University of Cambridge 2008 iii Paper 37 2 a Solution Created 2026-10-03 Updated 2026-10-14
Write and use the ordinary Euclidean Laplacian , so the generator of standard Brownian motion is half that operator. For a radial function , the Laplacian in polar coordinates is . With ,Thus is a harmonic function on the punctured space.
We first justify that the singularity is not visited. For , stop at . The Itô formula makes a local martingale, and it is bounded on this annulus, hence a true martingale. The exit time is finite almost surely: by the Gaussian transition density. Taking the bounded terminal limit yieldsIf the origin were reached before , every smaller radius would first be reached, so letting shows that event has probability zero. Taking a countable sequence proves almost surely. Localization on increasing annuli now applies the Itô formula globally and gives the Bessel power local martingaleStopping this continuous local martingale at any , including , preserves its local-martingale property.
For , the stopped path stays at radius at least , so . The bounded local martingale criterion makes it a true martingale. For , Brownian radial oscillations at its starting sphere give almost surely and the stopped process is constant. Thus the same true-martingale conclusion holds for .
For , the process is a strict local martingale. To prove this, write in distribution, with a standard -dimensional normal vector. For every shift ,Indeed the integrand outside the unit ball is at most one, while inside it the Gaussian density is at most and the radial integral is a constant times . Brownian scaling therefore givesA true martingale would have expectation at every time, which is impossible.
The printed range also permits , and this case must not be grouped with the bounded case. Here almost surely, by the same Gaussian bound for exit from a bounded ball. Moreover,since the second expectation is at most . It too is a strict local martingale. The complete stopped inverse radial power martingale classification is therefore
Past exam of the mathematics course of the University of Cambridge 2018 iii Paper 203 2 b Solution Created 2026-10-03 Updated 2026-10-05
Start the Bessel process at and let be its first hit of zero. Away from zero its stochastic differential equation isApply the Itô formula to , localizing first to a compact interval in . Its drift cancels:Thus the Bessel power local martingale satisfiesFor , this power is simply the constant one. For , it is a continuous local martingale for all time, as zero is inaccessible.
Here is a proof of that inaccessibility and of the stronger minimum assertion. For , stop the power at . The stopped process is bounded, so the optional stopping theorem givesExit from the bounded interval occurs almost surely. Taking with fixed shows that zero cannot be hit before , hence cannot be hit in finite time. Taking instead givesIf the all-time infimum were zero, every level below would be hit, by continuity. Letting proves the all-time minimum of a transient Bessel process assertion:The first claim in the printed question needs a qualification when : it holds before the first hit of zero, or for the process stopped there, rather than for the usual reflecting continuation. For example, at the proposed power is itself, a Reflected Brownian motion; the Tanaka formula contains a nonzero local time of a semimartingale term, so it is not a local martingale after reflection. A positive starting point is also needed for the negative power when ; an entrance process started at zero would give an infinite value at time zero.