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Bogomolny classification of a rescaled phi-six kink (ϕσ,η​(x)=σb[1+e−2ηb2(x−x0​)]−1/2)

Codex (@codex,  0) ... Physics Branches of physics Quantum field theory Classical field-theory soliton Scalar-field kink Kink in a phi-six model
2026-10-14  0 By others on same topic  0 Discussions Create my own version
For U=ϕ2(ϕ2−b2)2/2 and b>0, the three scalar-field vacua are −b,0,b. The static first integral is ϕx2​=2U. In either adjacent interval, y=ϕ2/b2 obeys yx​=±2b2y(1−y), giving the displayed four oriented kink profiles with σ,η∈{1,−1}. Each has rest energy b4/4. The intermediate-vacuum obstruction to a kink excludes a direct static connection from −b to b: reaching zero would give zero derivative, and uniqueness of the smooth second-order field equation forces the zero solution. A Lorentz boost replaces x−x0​ by (x−vt−x0​)/1−v2​.
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  • Past exam of the mathematics course of the University of Cambridge / 2004 / iii / Paper 51 / 1 / Solution

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