Bounded continuous functions 2026-10-07
Bounded continuous functions on a topological space form a Banach space with the supremum norm. A uniform limit is continuous and bounded, proving completeness. This space differs from the bounded uniformly continuous functions: free-transport composition is jointly continuous in time and position, but need not be continuous in the global sup norm as time varies.
Past exam of the mathematics course of the University of Cambridge 2013 iii Paper 6 2 d Solution Created 2026-10-03 Updated 2026-10-07
Fix an arbitrary finite and use the Banach space of bounded continuous functions with the supremum norm. Set . For in this space, the velocity integralis bounded by . If , the integrands converge pointwise and are bounded by the integrable function . The dominated convergence theorem proves continuity. Thus the rank-one gain on bounded continuous functions, , is continuous and bounded. The same theorem applied to the time integral shows that maps this space into itself, including at .
Time ordering gives the factorial bound for a Volterra iterate:Consequently the Volterra series for the linear Boltzmann equationconverges uniformly on the whole finite time slab, so its sum is continuous and bounded and satisfies the fixed point equation. Tracking the damping factors gives the sharper pointwise bound . This proves existence for every finite , without requiring or uniform continuity of . Boundedness on finite slabs does not assert a uniform bound over infinite time.
A bounded continuous factor and an integrable factor give a bounded velocity-integral gain on bounded continuous functions, with bound . The dominated convergence theorem proves joint continuity of the velocity integral. Combined with damped transport, the factorial bound for a Volterra iterate proves existence on arbitrary finite time slabs.