Past exam of the mathematics course of the University of Cambridge 2021 iii Paper 310 4 a Solution 2026-09-28
The creation and annihilation operators obeyThe two-point correlation function in their vacuum has Fourier amplitude . After cosmological horizon exit, , and the stated Bunch-Davies vacuum mode and giveThe dimensionless power spectrum is consequently
Past exam of the mathematics course of the University of Cambridge 2021 iii Paper 312 1 b Solution 2026-09-28
Since and , the interaction isto first order in . The tree-level in-in formalism givesThere are two Wick contractions for each choice of the undifferentiated field at the vertex. With , the stated Bunch-Davies vacuum mode obeysThe two powers of from the differentiated modes cancel , and the remaining integral isRemoving the momentum-conserving delta function, the bispectrum from a time-derivative cubic scalar interaction is therefore
Past exam of the mathematics course of the University of Cambridge 2021 ii Paper 1 15B d Solution Created 2026-09-24 Updated 2026-09-25
In the far past, , the term is negligible and the rescaled mode is a quantum harmonic oscillator of angular frequency . The stated choice of its ground state is the Bunch-Davies vacuum.
At late times, after the mode is far outside the Hubble scale, . Its variance becomesSince has dimensions of length cubed, the dimensionless power is proportional to . More precisely, with the standard isotropic Fourier convention,which is independent of the wavenumber . Thus equal logarithmic intervals in carry equal late-time power. This is the sense in which inflation naturally generates a scale-invariant inflationary power spectrum.
Past exam of the mathematics course of the University of Cambridge 2022 iii Paper 312 1 b Solution 2026-09-28
The positive-frequency solution for is proportional to . Since , its scalar-field mode function has the stated form . The canonical momentum in conformal time is , so the canonical commutation relation requires the Wronskian normalizationSubstitution gives . Hence, up to an irrelevant constant phase,The choice is the Bunch-Davies vacuum condition at early conformal time.
Past exam of the mathematics course of the University of Cambridge 2025 iii Paper 312 1 ii Solution Created 2026-09-24 Updated 2026-09-25
In one standard Schwinger-Keldysh propagator convention, suppressing the momentum delta function,The two bulk-to-boundary propagators to the late-time insertion areInterchanging every and gives the equivalent opposite contour-label convention. Direct differentiation of the supplied Bunch-Davies vacuum mode gives
Past exam of the mathematics course of the University of Cambridge 2026 iii Paper 312 1 i Solution Created 2026-09-24 Updated 2026-09-25
Write and evaluate derivatives of on the homogeneous backgroundThe first- and second-order changes in areAfter using the background equation to remove the linear action, the quadratic action of the P(X, phi) scalar field theory iswhereVarying gives
The Sound speed of a P(X, phi) scalar perturbation isAt leading slow variation, take , , and the kinetic coefficients as nearly constant and neglect the effective mass and their logarithmic derivatives. The Fourier equation then becomesFor and de Sitter spacetime , this isTwo independent solutions areThe Bunch-Davies vacuum selects the positive-frequency behavior as . Canonical normalization of gives the general amplitude; with the field normalization , so , it reduces, up to an overall phase, to
The Gaussian Bunch-Davies vacuum is selected by tilting the early endpoint to for integrands with . They then decay at the early boundary. The complex-conjugate integrand requires the opposite tilt. Ordered contractions and their contour must be conjugated together.