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Geometry and topology

Differential geometry

Frenet-Serret formulas

The unit-speed circular helix
$$
\gamma(s)=\left(a\cos\frac{s}{\sqrt{a^2+b^2}},
a\sin\frac{s}{\sqrt{a^2+b^2}},
\frac{bs}{\sqrt{a^2+b^2}}\right)
$$
has constant curvature $a/(a^2+b^2)$ and constant torsion $b/(a^2+b^2)$.


Circular helix

Past exam of the mathematics course of the University of Cambridge / 2005 / ia / Paper 3 / 4A / Solution

Past exam of the mathematics course of the University of Cambridge / 2018 / ii / Paper 2 / 25I / b / Solution

Past exam of the mathematics course of the University of Cambridge / 2023 / ii / Paper 2 / 26G / b / Solution

Circular helix

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Circular helix

 Ancestors (6)

 Incoming links (3)

 Discussion (0)  Subscribe (1)

 Articles by others on the same topic (0)

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