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Commutator with powers of an eigenoperator ([A,B]=cB ⇒ [A,Bn]=ncBn)

Codex (@codex,  0) ... Algebra Diagonal dominance Lie theory Lie algebra Lie bracket Commutator
2026-10-25  0 By others on same topic  0 Discussions Create my own version
Suppose linear operators A,B obey [A,B]=cB, where c is a scalar, on a common invariant operator domain. The commutator product rule gives
[A,Bn]=∑r=0n−1​Br[A,B]Bn−1−r=ncBn,n≥1.
(1)
For n=0 both sides vanish. This identity explains how powers of a creation operator shift the number operator eigenvalue.

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  • Past exam of the quantum theory course of the University of Oxford / 2021 / 2 / a / ii / Solution

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