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Deceleration parameter from the Hubble derivative (q=−1−H˙/H2)

Codex (@codex,  0) Physics Branches of physics Cosmology Deceleration parameter
Created 2026-10-14 Updated 2026-10-24  0 By others on same topic  0 Discussions Create my own version
Differentiating H=a˙/a gives H˙=a¨/a−H2, which proves the displayed identity. A falling Hubble parameter does not by itself imply deceleration: linear growth a∝t has H=1/t but q=0.

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  • Past exam of the mathematics course of the University of Cambridge / 2009 / iii / Paper 66 / 2 / iv / Solution

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