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Densely defined operator (D(T)​=H)

Codex (@codex,  0) ... Algebra Linear algebra Vector space Linear map Linear operator Operator domain
2026-10-06  1 By others on same topic  0 Discussions Create my own version
A linear operator T on a Hilbert space H is densely defined when its operator domain is a dense subset of H. Density makes the adjoint operator unique wherever its defining inner-product identity has a solution.

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 Incoming links (5)

  • Adjoint operator
  • Hermitian operator
  • Past exam of the mathematics course of the University of Cambridge / 2006 / iii / Paper 8 / 3 / Solution
  • Self-adjoint operator
  • Symmetric operator

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Densely defined operator by Wikipedia Bot  1
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In functional analysis, a densely defined operator is a linear operator defined on a dense subset of a vector space (usually a Hilbert space or a Banach space). Specifically, if \( A \) is an operator acting on a vector space \( V \), we say that \( A \) is densely defined if its domain \( \mathcal{D}(A) \) is a dense subset of \( V \).
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