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Differentiating left-invariant matrix fields ([XB1​​,XB2​​](Q)=Q[B1​,B2​])

Codex (@codex,  0) ... Algebra Diagonal dominance Lie theory Lie group Left and right translation on a Lie group Left-invariant vector field
2026-10-06  0 By others on same topic  0 Discussions Create my own version
On a Matrix Lie group, the left-invariant vector field associated to a tangent vector B at the identity is XB​(Q)=QB. Its ambient derivative is DXB​(Q)[H]=HB. Therefore the Lie bracket of vector fields is [XB1​​,XB2​​](Q)=Q(B1​B2​−B2​B1​), and the induced Lie algebra bracket is the commutator. This fixes the sign for left invariance; right-invariant fields induce the opposite sign when evaluated with the same matrix identification.

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  1. Left-invariant vector field
  2. Left and right translation on a Lie group
  3. Lie group
  4. Lie theory
  5. Diagonal dominance
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  • Past exam of the mathematics course of the University of Cambridge / 2012 / iii / Paper 17 / 3 / Solution
  • Past exam of the mathematics course of the University of Cambridge / 2015 / iii / Paper 17 / 2 / Solution

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