Double-longitudinal Ward identity for gluon fusion ($k_1^{\mu }{k}_2^{\nu }{\mathcal{M}}_{\mu \nu }=0$)

For massless $gg\to q\bar{q}$, define $i\mathcal{M}$ by the Feynman-rule product with quark vertex $ig{T}^a{\gamma }^{\mu }$. The ordered quark exchanges contribute $-g^2\bar{u}/k_1[T^a,T^b]v$ after double contraction. Three-gluon exchange contributes $i{g}^2{f}^{abc}\bar{u}/k_1{T}^{c}v$, so the sum vanishes by the Lie algebra. This does not assert off-shell transversality of each open index; the full Slavnov-Taylor identity includes Faddeev-Popov ghost terms.