Past exam of the mathematics course of the University of Cambridge 2022 ia Paper 4 3C b Solution Created 2026-09-24 Updated 2026-10-03
Let and , and choose . Part (a) gives . With the origin at , the remaining Cartesian components areThe initial conditions are . Integrating the second equation gives , soSolving this forced harmonic oscillator and then integrating yieldsThus the position vector is . The oscillation occurs at the signed cyclotron frequency, superposed on the usual E-cross-B drift.
Past exam of the symmetry and relativity course of the University of Oxford 2021 3 a ii Solution 2026-10-25
In the magnetic-dominated case the suitable Lorentz boost instead hasThe hypothesis gives . The electromagnetic field invariants now have , allowing a purely magnetic inertial frame. The initial velocity is again , perpendicular to . Since a magnetic field does no work, the electron's relativistic energy and speed in this inertial frame remain constant. Its trajectory is a circle in the plane with Lorentz factor and cyclotron frequency .
For , set and . A parametrization with the correct initial velocity and Lorentz force isTransforming the world line back to the laboratory givesThe laboratory trajectory is a stretched cycloid, with cusps at where the electron is momentarily at rest. It first accelerates toward , then curves toward , returning to its original coordinate each cycle while advancing in . Its mean drift is , the E-cross-B drift. Its laboratory kinetic energy oscillates as the electric field does positive and then negative work; it does not grow indefinitely. The strict inequalities in the two branches exclude the null case , where neither field can be removed by a finite Lorentz boost.