Past exam of the mathematics course of the University of Cambridge 2008 ii Paper 2 1H Solution Created 2026-09-24 Updated 2026-09-24
Past exam of the mathematics course of the University of Cambridge 2011 ii Paper 1 1I Solution Created 2026-09-24 Updated 2026-09-24
Past exam of the mathematics course of the University of Cambridge 2018 ii Paper 3 11G Solution Created 2026-09-24 Updated 2026-10-03
Write an integral binary quadratic form as , with discriminant of a binary quadratic form . It is positive definite when and . Two forms are equivalent if one is obtained from the other by an integral linear change of variables whose matrix lies in . A positive definite form is reduced whenwith when or .
To reduce a form, apply a unimodular shear with chosen so that the new middle coefficient has . If the new final coefficient is smaller than , exchange the variables, using a determinant-one rotation, so that the positive leading coefficient decreases from to . Repeating must stop because a positive integer cannot decrease indefinitely. At termination , and elementary sign changes impose the boundary convention. This is the reduction algorithm for a positive definite binary quadratic form, and proves that every positive definite form is equivalent to a reduced one.
The displayed forms have discriminant , so the intended discriminant is . For any reduced form of this discriminant, enumeration of reduced binary quadratic forms givesThe boundary convention and direct checking of leave only
Suppose first that a prime is represented by . The identityshows modulo both and that is a nonzero square. HenceSimilarly,Modulo , this says is a square, while modulo it says is a square. Since , the multiplicativity of the Legendre symbol gives
Conversely, suppose the two displayed Legendre symbols have the same sign. By quadratic reciprocity,Choose an odd integer satisfying . Since is odd, is also divisible by , sois a positive definite integral form of discriminant that represents . Reducing yields either or , and equivalence preserves represented integers. The necessary symbol calculation above determines which one: the positive pair selects , and the negative pair selects . Therefore
Past exam of the mathematics course of the University of Cambridge 2023 ii Paper 3 11G Solution Created 2026-09-23 Updated 2026-09-25
Write an integral binary quadratic form asA positive definite form is a reduced positive definite binary quadratic form whenwith on the boundary or . The class number of a negative discriminant is the number of proper equivalence classes of primitive positive definite integral forms of discriminant .
Every such class has a reduced representative. For a reduced form,soThere are only finitely many possible integers and , and thenis determined. Hence . There is at least one class: the principal form isandThus , in agreement with the enumeration of reduced binary quadratic forms.
Now let be prime. The two formsare primitive, positive definite, reduced, and have discriminant . They are not properly equivalent: represents one, while the least positive value of is two. Therefore
Assume henceforth that , so these are the only two classes. Iffor a prime , then is odd andMoreover , so is a quadratic residue modulo . This proves the necessity.
Conversely, suppose and is a quadratic residue modulo . By quadratic reciprocity, these two conditions implyIndeed, for both relevant signs are positive, while for the signs from and reciprocity with cancel. Choose an even integer such thatThenis a primitive positive definite integral form of discriminant and represents . It belongs to one of the two classes .
The second form cannot represent such a prime. Ifthen is odd and, since ,This contradicts . Hence lies in the principal class , and proper equivalence of binary quadratic forms preserves represented integers. ThereforeThis is the prime representation when h of minus eight q equals two.