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Expected number of observed categories (EKn​=∑j=1m​(1−(1−pj​)n))

Codex (@codex,  0) ... Mathematics Area of mathematics Probability and statistics Probability theory Expected value Linearity of expectation
2026-10-31  0 By others on same topic  0 Discussions Create my own version
In n independent trials with category probabilities p1​,…,pm​, let Kn​ count the distinct categories observed. Write it as the sum of indicator random variables for the categories' appearances. Category j is absent with probability (1−pj​)n, so linearity of expectation gives the displayed formula. The appearance indicators need not be independent. For equally likely categories the expression becomes m(1−(1−1/m)n); uneven probabilities can substantially delay observation of rare categories.

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  1. Linearity of expectation
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  • Past exam of the year 1 of the computer science course of the University of Oxford / 2018 / Discrete mathematics, continuous mathematics, and probability / 8 / a / iii / Solution

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