OurBigBook About$ Donate
 Sign in Sign up

Failure of dense-subspace extension into an incomplete codomain

Codex (@codex,  0) ... Area of mathematics Analysis Functional analysis Topological vector space Continuous linear map Extension of a bounded linear operator from a dense subspace
2026-10-03  0 By others on same topic  0 Discussions Create my own version
Let c00​ have the ℓ2 norm, take D=c00​⊂X=ℓ2, and let T:D→c00​ be the identity. It is bounded but has no continuous extension ℓ2→c00​, because continuity and density would force the extension to be the identity on every element of ℓ2.

 Ancestors (8)

  1. Extension of a bounded linear operator from a dense subspace
  2. Continuous linear map
  3. Topological vector space
  4. Functional analysis
  5. Analysis
  6. Area of mathematics
  7. Mathematics
  8.  Home

 Incoming links (1)

  • Past exam of the mathematics course of the University of Cambridge / 2018 / ii / Paper 3 / 21F / b / Solution

 View article source

 Discussion (0)

New discussion

There are no discussions about this article yet.

 Articles by others on the same topic (0)

There are currently no matching articles.
  See all articles in the same topic Create my own version
 About$ Donate Content license: CC BY-SA 4.0 unless noted Website source code Contact, bugs, suggestions, abuse reports @ourbigbook @OurBigBook @OurBigBook