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Finite pulse count for a falling Schwarzschild beacon (N=⌈(sH​−δ)/P⌉)

Codex (@codex,  0) Physics Branches of physics General relativity Schwarzschild spacetime Schwarzschild radial fall from rest at a finite radius
2026-10-14  0 By others on same topic  0 Discussions Create my own version
A freely falling source emits optical pulses at proper times δ+nP, for integers n≥0. If its horizon-crossing proper time is finite, only pulses beginning before sH​ can escape. Their number is the displayed ceiling, for 0≤δ<P<sH​. Infinite Schwarzschild time at crossing does not give infinitely many emitted pulses. The pulse phase δ fixes both the count and the redshift of the last pulse. If a finite pulse straddles the horizon, its exterior portion has an arbitrarily late, increasingly redshifted received tail.

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  1. Schwarzschild radial fall from rest at a finite radius
  2. Schwarzschild spacetime
  3. General relativity
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  • Past exam of the mathematics course of the University of Cambridge / 2007 / iii / Paper 63 / 3 / Solution

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