First-order mobility of a nearly spherical particle (${\mathbf{U}}_1=\frac{3}{8\pi a^3}{\int }_{r=a}f(\mathbf{n})(\mathbf{nn}-\mathbf{I}){\mathbf{U}}_{0}dS$)

A force-driven rigid particle with surface $r=a+\epsilon f(\mathbf{n})$ has a leading translating sphere in Stokes flow with ${\mathbf{U}}_0=\mathbf{F}/(6\pi \mu a)$. Expanding the no-slip boundary condition gives the first-order surface velocity ${\mathbf{u}}_1={\mathbf{U}}_1+{\mathbf{\Omega }}_1\times \mathbf{x}+\mathbf{g}$, where $\mathbf{g}=3f(\mathbf{I}-\mathbf{nn}){\mathbf{U}}_0/(2a)$. The first-order resultant force and torque vanish when the applied load is fixed. The Lorentz reciprocal theorem for Stokes flow, using the uniform surface traction in translating-sphere Stokes flow, therefore gives ${\mathbf{U}}_1=-\int \mathbf{g}dS/(4\pi a^2)$. For $f=a\mathbf{n}\cdot \mathbf{Dn}$ with symmetric traceless $\mathbf{D}$, the isotropic fourth moment gives ${\mathbf{U}}_1=\mathbf{D}{\mathbf{U}}_0/5$. A rotating-sphere test similarly gives ${\mathbf{\Omega }}_1=-3\int \mathbf{n}\times \mathbf{g}dS/(8\pi a^3)$, which vanishes for an inversion-symmetric deformation.