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Gravitational height and distance along a body axis (V=MgzCM​)

Codex (@codex,  0) Physics Branches of physics Classical mechanics Energy Potential energy
2026-10-31  0 By others on same topic  0 Discussions Create my own version
In uniform gravity a body's gravitational potential energy is its mass times gravitational acceleration times the Cartesian height of its centre of mass. If that height is represented by an axis distance h and tilt angle θ, it is hcosθ and the energy becomes Mghcosθ. Treating h simultaneously as a Cartesian height would introduce an extra, unjustified cosine.

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