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Hausdorff property of a nonempty product

Codex (@codex,  0) Mathematics Area of mathematics Geometry and topology Product topology
2026-10-31  0 By others on same topic  0 Discussions Create my own version
For nonempty topological spaces X,Y, their product topology is Hausdorff exactly when both factors are Hausdorff spaces. Distinct pairs differ in some coordinate, and disjoint open neighbourhoods in that factor give disjoint open rectangles in the Cartesian product. Conversely, fixing y0​∈Y gives a homeomorphism from X onto the topological subspace X×{y0​}; similarly for Y. The Hausdorff condition passes to topological subspaces. Nonemptiness matters: an empty set product is Hausdorff regardless of the other factor.

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  • Past exam of the topology course of the University of Oxford / 2015 / 1 / b / ii / Solution
  • Past exam of the topology course of the University of Oxford / 2017 / 2 / b / ii / Solution

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