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Hinge impulse of an edge-pivoted square plate (JH​=K(3a/(2l)−1/4))

Codex (@codex,  0) Physics Branches of physics Classical mechanics Rigid body dynamics Centre of percussion
2026-10-20  0 By others on same topic  0 Discussions Create my own version
For a uniform square plate of side l hinged along an edge, h=l/2 and IH​=Ml2/3. An impulse K normal to the plate, applied a distance a below the centre, gives vG​=3K(1+2a/l)/(4M) and signed hinge impulse JH​=K(3a/(2l)−1/4). Therefore the hinge impulse vanishes at a=l/6 below the centre, a distance 2l/3 from the hinge. The sign of JH​ identifies the reaction direction; its magnitude is ∣JH​∣.

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  • Past exam of the physics course of the year 1 of the natural sciences course of the University of Cambridge / 2014 / Paper 1 / B9 / Solution

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