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Phi-four diffuse interface

{title2=$\sigma$}

The excess free energy per area of the phi-four diffuse interface is
$$
\sigma=\int_{-\infty}^{\infty}\kappa(\phi')^2dx
=\sqrt{\frac{-8a^3\kappa}{9b^2}}.
$$


Interfacial tension of a phi-four diffuse interface

Past exam of the mathematics course of the University of Cambridge / 2023 / iii / Paper 344 / 1 / f / Solution

Interfacial tension of a phi-four diffuse interface ( $σ$ )

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