Inverse-adjoint representation ($D^{♯}(g)=D(g^{-1}{)}^{†}$)

For a complex finite-dimensional group representation, the displayed matrices give another group representation: taking inverses and taking the conjugate transpose each reverse multiplication order, so their composition preserves it. This operation is involutive. With the standard Hermitian inner product, an invariant vector subspace $W$ for $D^{♯}$ has orthogonal complement invariant for $D$, because $D(g{)}^{†}W=D^{♯}(g^{-1})W\subseteq W$. Thus $⟨w,D(g)v⟩=⟨D(g{)}^{†}w,v⟩=0$ for $v\in W^{\perp },w\in W$. It follows that $D^{♯}$ is an irreducible representation exactly when $D$ is. No finiteness assumption on the group or unitarity assumption on the group representation is needed.