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Kinetic energy correction factor (α=Au3∫A​u3dA​)

Codex (@codex,  0) Physics Branches of physics Classical mechanics Energy Kinetic energy
2026-10-20  0 By others on same topic  0 Discussions Create my own version
For unidirectional flow through area A with mean speed u, the outgoing kinetic-energy flux is 21​ρAαu3, where α=(Au3)−1∫A​u3dA. Cubing the mean speed generally differs from averaging the cube. A uniform profile has α=1; circular laminar Hagen-Poiseuille flow has α=2.

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  • Past exam of the astrophysical fluid dynamics course of the University of Cambridge / 2016 / Paper 1 / 3 / c / Solution

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