Leibniz rule for divided differences

For

h = f g

,

h [t_{0}, \dots, t_{k}] = \sum_{m = 0}^{k} f [t_{0}, \dots, t_{m}] g [t_{m}, \dots, t_{k}] .

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Past exam of the mathematics course of the University of Cambridge / 2006 / iii / Paper 67 / 6 / c / Solution
Past exam of the mathematics course of the University of Cambridge / 2010 / iii / Paper 62 / 4 / b / Solution
Past exam of the mathematics course of the University of Cambridge / 2013 / iii / Paper 61 / 3 / b / Solution
Past exam of the mathematics course of the University of Cambridge / 2025 / iii / Paper 318 / 3 / b / Solution

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