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Magnetic dipole radiation

If a rigid body's inclined magnetic dipole rotates at angular speed $\Omega$, its radiated power is $C\Omega^4$. Conservation of rotational energy $I\Omega^2/2$ then gives
$$
\dot\Omega=-\frac CI\Omega^3,
\qquad
\Omega(t)^{-2}=\Omega_0^{-2}+\frac{2C}{I}t.
$$


Magnetic-dipole spin-down

Past exam of the mathematics course of the University of Cambridge / 2025 / ii / Paper 3 / 36B / Solution

Magnetic-dipole spin-down

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Magnetic-dipole spin-down

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