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Maximum dimension of a totally isotropic subspace (n−(r+∣s∣)/2)

Codex (@codex,  0) ... Area of mathematics Algebra Linear algebra Quadratic form Isotropic quadratic form Totally isotropic subspace
2026-10-05  0 By others on same topic  0 Discussions Create my own version
For a real quadratic form on an n-dimensional vector space, with rank r and signature s defined as positive minus negative index, the maximum dimension of a totally isotropic subspace is n−(r+∣s∣)/2. Quotienting by the radical of a bilinear form leaves a nondegenerate form of indices p,q. Projection of an isotropic subspace to each sign-coordinate space is injective, bounding its dimension by min(p,q). The radical and vectors pairing one positive with one negative unit coordinate attain the bound n−r+min(p,q).

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  1. Totally isotropic subspace
  2. Isotropic quadratic form
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  • Past exam of the mathematics course of the University of Cambridge / 2017 / ib / Paper 3 / 10F / Solution

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